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9n^2-18n-78=0
a = 9; b = -18; c = -78;
Δ = b2-4ac
Δ = -182-4·9·(-78)
Δ = 3132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3132}=\sqrt{36*87}=\sqrt{36}*\sqrt{87}=6\sqrt{87}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{87}}{2*9}=\frac{18-6\sqrt{87}}{18} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{87}}{2*9}=\frac{18+6\sqrt{87}}{18} $
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